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  • The Young's modulus of brass and steel are <img alt="1.0 \times 10^{10} \, N/ m^{2}" src="https://entrancecorner.oncodecogs.com/gif.latex?1.0%20%5Ctimes%2010%5E%7B10%7D%20%5C%2C%20N/%20m%5

The Young's modulus of brass and steel are 1.0 \times 10^{10} \, N/ m^{2} and 2 \times 10^{10} \, N/ m^{2} respectively. A brass wire and a steel wire of the same length are extended by 1mm under the same force, the radii of brass and steel wires are RB and RS respectively. Then-

Option: 1

R_S=\sqrt{2} R_B


Option: 2

R_S=\frac{R_B}{\sqrt{2}}


Option: 3

R_S=4 R_B


Option: 4

R_S=\frac{R_B}{4}


Answers (1)

best_answer

\Delta l =\frac{F_l}{A_y} = \frac{F_l}{\Pi R^2Y}

\Delta l, F \: and\: l \: are\: same.\\ Hence, R^2 = Constant

 \frac{R_S}{R_B} = \sqrt{\frac{Y_B}{Y_S}} = \sqrt{\frac{1}{2}}

{R_S} = \frac{R_B}{\sqrt{2}}

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shivangi.shekhar

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