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Thermal capacity (in J/K) of 18 g water is (s= 1cal/g-K) 

 

Option: 1 75.6

Option: 2 66.5

Option: 3 56.6

Option: 4 86.5

Answers (1)

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As we have learned

Thermal Capacity -

mc=\mu c=\frac{Q}{\Delta \theta}

-

 

 Thermal capacity = ms = 18 * 1 cal / K 

= 18 * 4.2 J / K = 75.6 J/k 

 

Posted by

Ritika Kankaria

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