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  • True initial rate of zero-order reaction of the gaseous reaction <img alt="A(g)\rightarrow 2B(g)\: \: is\: \: 10^{-2}M\, min^{-1}" src="http://entrancecorner.oncodecogs.com/gif.latex?A%28g%29%

True initial rate of zero-order reaction of the gaseous reaction A(g)\rightarrow 2B(g)\: \: is\: \: 10^{-2}M\, min^{-1}. If the initial concentration of A is 0.1M, after 60 sec concentration of B (in M) should be:

Option: 1

0.02


Option: 2

0.01


Option: 3

0.09


Option: 4

0.002


Answers (1)

best_answer

Zero Order Reaction -
Zero-order reaction means that the rate of the reaction is proportional to zeroth power of the concentration of reactants
 

Rate=\frac{-d(R)}{dt}=K[R]^{0}=K

Now,

\\rate=.01 M/min \\\\rate =\frac{0.01}{60}M/sec

\begin{array}{l}{[A] \rightarrow 2[B]} \\\\ {[A] \text { taking the part of reaction in 60 sec }} \\\\ {[A]=60 \times \frac{0.01}{60} \mathrm M} \\\\ {\text { so, }[B]=2 \times 60 \times \frac{0.01}{60} \mathrm M=0.02 \: \mathrm M}\end{array}

 

Posted by

Ritika Jonwal

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