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Equation y = 5\sin\frac{\pi x}{3}\cos40\pi t is given. Find the seperation between two adjecent node

  • Option 1)

    1.5 cm

  • Option 2)

    3 cm

  • Option 3)

    6 cm

  • Option 4)

    4 cm

 

Answers (1)

best_answer

From comparision \frac{2\pi X}{\lambda }= \frac{\pi X}{3}= \lambda =6

so dist is \frac{\lambda }{2}= 3cm

 

Equation of stationary waves -

y_{1}= A\sin \left ( kx- \omega t \right )

y_{2}= A\sin \left ( kx+ \omega t \right )

 

- wherein

Resultant wave

y= \left ( 2A\sin kx.\cos \omega t \right )

 

 


Option 1)

1.5 cm

This is incorrect

Option 2)

3 cm

This is correct

Option 3)

6 cm

This is incorrect

Option 4)

4 cm

This is incorrect

Posted by

Avinash

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