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  • Two beams of light having intensities I and 4 / interfere to produce a fringe pattern on a screen. The phase difference between the beams is <img alt="\mathrm{\frac{\pi}{2}}" src="https:/

Two beams of light having intensities I and 4 / interfere to produce a fringe pattern on a screen. The phase difference between the beams is \mathrm{\frac{\pi}{2}} at point A and \pi at point B. Then the difference between the resultant intensities at A and B is

Option: 1

2/


Option: 2

4/


Option: 3

5/


Option: 4

7/


Answers (1)

best_answer

At point A, resultant intensity

\mathrm{\mathrm{I}_{\mathrm{A}}=\mathrm{I}_1+\mathrm{I}_2=5 \mathrm{l}; and \, \, at \, \, point \, \, B}

\mathrm{ \begin{aligned} & \mathrm{I}_{\mathrm{B}}=\mathrm{I}_1+\mathrm{I}_2+2 \sqrt{\mathrm{I}_1 \mathrm{I}_2} \cos \pi=5 \mathrm{I}+4 \mathrm{I} \\ & \mathrm{I}_{\mathrm{B}}=9 \mathrm{I} \text { so } \mathrm{I}_{\mathrm{B}}-\mathrm{I}_{\mathrm{A}}=4 \mathrm{I} . \end{aligned} }

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shivangi.bhatnagar

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