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  • Two blocks of masses 50 Kg and 30 Kg connected by a massless string pass over a tight frictionless, pulley and rest on two smooth planes inclined at angles <img alt="30 \degree" src="http://en

Two blocks of masses 50 Kg and 30 Kg connected by a massless string pass over a tight frictionless, pulley and rest on two smooth planes inclined at angles 30 \degree and respectively with horizontal as shown in the figure. If the system is released from rest then find the time taken by 30 Kg block to reach the ground 

Option: 1

20 sec 


Option: 2

30 sec 


Option: 3

10 sec 


Option: 4

50 sec 


Answers (1)

best_answer

As we have learned

Double inclined plane with different angles -

 

- wherein

a=\frac{(m_{2}\:sin\theta_{2}-m_{1}\:sin\theta_{1})g}{m_{1}+m_{2}}


T=\frac{m_1m_2(sin\theta_1+sin\theta_2)\:g}{m_1+m_2}

 

 

 T - 50g \sin 30 = 50a ....(1) \\ 30 g \sin 60 - T = 30 a .....(2)

Adding (1)  and (2) 

a = \frac{30g \sin 60 - 50g \sin 30 }{80 } = 0.12 m /s

Now

 s = ut + 1/2 at^2 \\ 6 =(1/2)\times 0.12 \times t^2 \\ t^2 = \frac{6 \times 2}{0.12} = 100 \\ \\ t = 10 sec

Posted by

Kuldeep Maurya

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