-
Engineering and Architecture
Exams
Colleges
Predictors
Resources
-
Computer Application and IT
Quick Links
Colleges
-
Pharmacy
Colleges
Resources
-
Hospitality and Tourism
Colleges
Resources
Diploma Colleges
-
Competition
Other Exams
Resources
-
School
Exams
Top Schools
Products & Resources
-
Study Abroad
Top Countries
Student Visas
-
Arts, Commerce & Sciences
Exams
Colleges
Upcoming Events
Resources
-
Management and Business Administration
Colleges & Courses
Predictors
-
Learn
Online Courses
Engineering Preparation
Medical Preparation
-
Online Courses and Certifications
Top Streams
Specializations
- Digital Marketing Certification Courses
- Cyber Security Certification Courses
- Artificial Intelligence Certification Courses
- Business Analytics Certification Courses
- Data Science Certification Courses
- Cloud Computing Certification Courses
- Machine Learning Certification Courses
- View All Certification Courses
Resources
-
Medicine and Allied Sciences
Colleges
Predictors
Resources
-
Law
Resources
Colleges
-
Animation and Design
Predictors & Articles
Colleges
Resources
-
Media, Mass Communication and Journalism
Colleges
Resources
-
Finance & Accounts
Top Courses & Careers
Colleges
Get Answers to all your Questions
- Home
- Engineering
- Two elements with electronegativities are 1.2 and 3.2 respectively, the bond formed between them will be:Option: 1 Covalent<div class='
- #Joint Entrance Examination Main
- #Classification of Elements and Periodic table
- #National Eligilibility Cum Entrance Test
- #Chemistry
- #Engineering
Two elements with electronegativities are 1.2 and 3.2 respectively, the bond formed between them will be:
Covalent
Metallic
Ionic
None
Answers (1)
Electronegativity -
Nature of Bond: From the electronegativity values of respective atoms, the nature of the bond can be estimated.
(i) When the electronegativity difference between two atoms i.e, MA- MB = 0, then the bond is purely covalent.
(ii) When MA - MB is small, then the bond is polar but covalent.
(iii) When MA - MB is 1.9, then the bond is 50% ionic and 50% covalent.
(iv) When MA - MB is more than 1.9, the bond is very much ionic and less covalent.
The percentage of ionic character is given by the following formula:
Percentage of ionic character = 16(MA - MB) + 3.5(MA - MB)2
Where MA and MB are the electronegativities of two bonded atoms i.e, A and B.
For the formation of the ionic bond, the electronegativity difference between the constituent atoms must be more than 1.9.
Therefore, Option(3) is correct
JEE Main high-scoring chapters and topics
Study 40% syllabus and score up to 100% marks in JEE
