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  •  Two light waves are given by, <img alt="E_1 = 2 \sin ( 100 \pi t - kx + 30 ) \: \: and \: \: E_ 2 = 3 \cos ( 200 \pi t - k x + 60 )" src="https://entrancecorner.oncodecogs.com/gif.latex?

 Two light waves are given by, E_1 = 2 \sin ( 100 \pi t - kx + 30 ) \: \: and \: \: E_ 2 = 3 \cos ( 200 \pi t - k x + 60 )

The ratio of intensity of first wave to that of second wave is : 

Option: 1

2/3 


Option: 2

4/9 


Option: 3

1/9 


Option: 4

1/3 


Answers (1)

best_answer

as we learned

Intensity of EM wave -

I = \frac{1}{2} \epsilon _{o} E_{o}^{2}c

- wherein

\epsilon _{o} = Permittivity of free space

E _{o} = Electric field amplitude

c = Speed of light in vacuum

 

 

 so

I \propto A ^2 \therefore \frac{I_1 }{I_2} = \frac{2^2 }{3^2 } = 4/9

Posted by

Anam Khan

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