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  • Two pulses travel on the same string are described by -  <img alt="y_1 = \frac{5}{(3x-4t)^2+2} \ \ \ \ and \ \ \ \ \ y_2 = \frac{-5}{(3x+4t-6)^2+2}" src="http://entrancecorner.oncode

Two pulses travel on the same string are described by - 

y_1 = \frac{5}{(3x-4t)^2+2} \ \ \ \ and \ \ \ \ \ y_2 = \frac{-5}{(3x+4t-6)^2+2}

Then at which instant they do cancel everywhere? (in seconds)

Option: 1

0.75


Option: 2

0.5


Option: 3

1


Option: 4

1.25


Answers (1)

best_answer

 

 

 

We require -

 y_1 +y_2 = 0 \\ \\ \Rightarrow \frac{5}{(3x-4t)^2+2}+ \frac{-5}{(3x+4t-6)^2+2}

This can be written as - 

(3x-4t)^2 = (3x+4t-6)^2

After solving , t = 0.75 Seconds

Posted by

Anam Khan

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