Get Answers to all your Questions

header-bg qa

Two wires with current 2A and 1A are enclosed in a circular loop. Another wire with current 3A is situated outside the circular loop. The \int {B}\cdot \vec{dl}   around the loop is

Option: 1

\mu _{0}


Option: 2

3\mu _{0}


Option: 3

6\mu _{0}


Option: 4

2\mu _{0}


Option: 5

Zero


Answers (1)

best_answer

As we learned

Ampere's Law -

It gives another method to calculate the magnetic field due to the given current distribution. 

Another wire with current 3A is situated outside the loop as shown-

 According to Ampere's circuital law 

\oint \vec{B}\cdot \vec{dl}=\mu _{0}I_{enclosed}=\mu _{0}(2A-1A)=\mu _{0}

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE