1. 20/11 \mu C

  2. 90/11 \mu C

  3. 10 \mu C

  4. 110 \mu C

Answers (1)
S Sayak

Let the equivalent capacitance of the thre capacitors connected in series be C

\\\frac{1}{C}=\frac{1}{2}+\frac{1}{3}+\frac{1}{6} \\C=1\ \mu F

Since the capacitors are connected on series same charge will be accumulated on all of them.

Charge accumulated on 2\ \mu F capacitor=1\times 10=10\ \mu C

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