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What is the magnitude of magnetic field (in $\mu T$ ) at the center of the current carrying ring placed in air having current 2 Ampere and radius equals to 4 $\pi$ meter ?
Option: 1
1

Option: 2
0.1

Option: 3
0.4

Option: 4
10

Answers (1)

best_answer

$\\ Since \ the \ number \ of \ turn = 1 \\ And \ we \ know \ that = B = \frac{\mu_o I}{2R} \\ \Rightarrow B = \frac{4 \pi \times 10^{-7} \times 2}{2 \times 4 \pi} = 10^{-7} \ Tesla$

$B = 0.1 \ \mu T$

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