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  • What will be the manification formula in the mentioned figure, where v = position of image from the pole and u = position of the object from the pole -        &nb

What will be the manification formula in the mentioned figure, where v = position of image from the pole and u = position of the object from the pole - 

                                              

Option: 1

m=-\frac{v / \mu_{2}}{u / \mu_{1}}


Option: 2

m=-\frac{u / \mu_{2}}{v / \mu_{1}}


Option: 3

m=-\frac{v / \mu_{1}}{u / \mu_{2}}


Option: 4

None \ of \ the \ above


Answers (1)

best_answer

\text { Lateral magnification, } m=\frac{\text { Image height }}{\text { Object height }}=\frac{-\left(A^{\prime} B^{\prime}\right)}{A B}

or m=-\frac{A^{\prime} B^{\prime}}{A B}=-\frac{\mu_{1}}{\mu_{2}} \times \frac{v}{u}=-\frac{v / \mu_{2}}{u / \mu_{1}}

where

 \mu _1=Refractive index of the medium from which light rays are coming (from the object).

\mu _2=Refractive index of the medium in which light rays are entering.

and \mu _1< \mu _2

and u = Distance of object, v = Distance of image, R = Radius of curvature

 

-

 

 

Posted by

manish painkra

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