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  • What will be the time period can a simple pendulum whose length is 3200 Km and take the value of acceleration due to gravity = 10 m/s2 ?(Give answer in minutes)<div class='

What will be the time period can a simple pendulum whose length is 3200 Km and take the value of acceleration due to gravity = 10 m/s2 ?(Give answer in minutes)

Option: 1

7.69


Option: 2

3.69


Option: 3

76.9


Option: 4

36.9


Answers (1)

T= 2\pi \sqrt{\frac{1}{g\left ( \frac{1}{l}+\frac{1}{R} \right )}}

T = 2 \pi \sqrt{\frac{1 \times 10^3}{10(\frac{1}{3200}+\frac{1}{6400})}}

T = \frac{80 \times 10}{\sqrt 3} = 461.880 \ seconds = 7.69 \ minutes

Posted by

Sumit Saini

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