4g of impure CaCO3 on treatment with excess HCl produces 0.88 g CO2. What is the percent purity of CaCO3 sample?
A.75
B.25
C.90
D.50
here, In 44g of ------> 100g of
So, for 0.88g of CO2 -----> (100/44)*0.88 g = 2g
but in question we have 4g so here we conclude that 2 g is pure CaCO3& 2g is impure.
% of purity = 2/4 *100 = 50%
the option C IS correct
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