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  • When a body is projected from height h parallel to horizontal with velocity u then equation of trajectory of body is (taking upward direction as positive y - axis)  -<div class='qna-option

When a body is projected from height h parallel to horizontal with velocity u then equation of trajectory of body is (taking upward direction as positive y - axis)  -

Option: 1

y=\frac{1}{2}g\frac{x^{2}}{u^{2}}
 


Option: 2

y=\frac{1}{2}g\frac{u^{2}}{x^{2}}


Option: 3

y=-\frac{1}{2}g\frac{x^{2}}{u^{2}}

 


Option: 4

y=-\frac{1}{2}g\frac{u^{2}}{x^{2}}


Answers (1)

best_answer

Equation of path of a projectile

y= \frac{g}{2u^{2}}.x^{2}   

          g\rightarrow    Acceleration due to gravity

          u\rightarrow initial velocity

because, 

\\x=u\times t=ut\Rightarrow t=\frac{x}{u}\\* y=ut-\frac{1}{2}gt^{2}= -\frac{1}{2}gt^{2}\\* So\: \: y= -\frac{1}{2}g\left [ \frac{x}{u} \right ]^{2}

Posted by

Ritika Jonwal

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