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When a graph is plotted between \log \frac{x}{m} and log p, it is straight line with an angle of 450 and intercept 0.3010 on y-axis. If the initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent  :

Option: 1

0.4


Option: 2

0.6


Option: 3

0.8


Option: 4

0.1


Answers (1)

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Logarithmic graph of Freundlich isotherm -

\\\mathrm{\log \frac{x}{M}= \log k+\frac{1}{n}\log P } \\\\\textup{Given},\\\\ \frac{1}{n}=\tan 45^{0} \text { and } \log \mathbf{k}=0.3010 \\\\ \textrm{ Hence, n=1 and k=2.}

\frac{\mathbf{x}}{\mathrm{m}}=\mathbf{k} \times \mathrm{P}^{\mathbf{1}}

\begin{array}{l} \text {Therefore, } \\\\\frac{x}{m}=2 \times(0.3)^{1} . \\\\ \text {or } x=0.6 \end{array}

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