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When Cu turning is heated with conc. HNO₃ it give -
Option: 1
NO₂

Option: 2
NO

Option: 3
N₂O

Option: 4
NH₄NO₃

Answers (1)

best_answer

As we have learnt,

Formation of nitrogen dioxide with conc. nitric acid -

By heating copper turnings with conc. HNO₃

- wherein

$Cu+4HNO_{3}\rightarrow Cu\left ( NO_{3} \right )_{2}+2H_{2}O+2NO_{2}$

$Cu+4HNO_{3}\rightarrow Cu\left ( NO_{3} \right )_{2}+2H_{2}O+2NO_{2}$

Posted by

jitender.kumar

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