Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • When excess of react with <img alt="\mathrm{F_2}" src="https://entrancecorner.oncodecogs.com/g

When excess of \mathrm{Xe} react with \mathrm{F_2} then it forms:

Option: 1

\mathrm{XeF _{2}}


Option: 2

\mathrm{XeF _{4}}


Option: 3

\mathrm{XeF _{6}}


Option: 4

\mathrm{X e_{2} F_{5}}


Answers (1)

best_answer

As we have learnt,

Xe forms a series of compounds with Fluorine depending on the relative quantity of \mathrm{Xe} and \mathrm{F_2}

The reactions are given as 

\mathrm{Xe + F_2\longrightarrow XeF_{2}; \text{(Xe in excess)}}

\mathrm{Xe + 2F_2 \longrightarrow XeF_{4}; \mathrm{(Xe:F_2=1:5)}}

\mathrm{Xe + 3F_2 \longrightarrow XeF_{6}; \mathrm{(Xe:F_2=1:20)}}

Therefore, option (1) is correct.

Posted by

Gautam harsolia

View full answer

Similar Questions

Latest Question