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  • When the electron in the hydrogen atom jumps from 2nd orbit to 1st orbit, the wavelength of radiation emitted is . When the

When the electron in the hydrogen atom jumps from 2nd orbit to 1st orbit, the wavelength of radiation emitted is \lambda. When the electrons jump from 3rd orbit to 1st orbit, the wavelength of emitted radiation would be

Option: 1

\frac{27}{32}\lambda


Option: 2

\frac{32}{27}\lambda


Option: 3

\frac{2}{3}\lambda


Option: 4

\frac{3}{2}\lambda


Answers (1)

best_answer

\mathrm{\frac{1}{\lambda}=R\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]}

\mathrm{\text{First condition }\frac{1}{\lambda}=R\left[\frac{1}{1^2}-\frac{1}{2^2}\right] \Rightarrow R=\frac{4}{3 \lambda}}
\mathrm{\text{Second condition }\frac{1}{\lambda^{\prime}}=R\left[\frac{1}{1^2}-\frac{1}{3^2}\right]}

\mathrm{\Rightarrow \lambda^{\prime}=\frac{9}{8 R} \Rightarrow \lambda^{\prime}=\frac{9}{8 \times \frac{4}{3 \lambda}}=\frac{27 \lambda}{32}}

Posted by

vishal kumar

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