Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Which of the following has a square planar geometry?Option: 1 <img alt="\mathrm{\left[P t C l_{4}\right]^{2-}}" src="https://entrancecorner.oncodecog

Which of the following has a square planar geometry?

Option: 1

\mathrm{\left[P t C l_{4}\right]^{2-}}


Option: 2

\mathrm{\left[ NiCl _{4}\right]^{2-}}


Option: 3

\mathrm{\left[ FeCl _{4}\right]^{2-}}


Option: 4

\mathrm{\left[C u C l_{4}\right]^{2-}}


Answers (1)

best_answer

As we have learnt,

Electronic configuration of \mathrm{Pt} and \mathrm{Pt^{2+}} are given as 

\mathrm{Pt: [Xe] 4f^{14} 5d^9 6s^1}

 \mathrm{Pt^2^+: [Xe] 4f^{14} 5d^8}

Now, as Pt belongs to the 5d series, weaker ligands are also able to cause pairing because of greater splitting due to larger size of the orbiratal.

Hence, it has \mathrm{dsp^2} hybridisation and square planar geometry.

-

Electronic configuration of\mathrm{Ni^2^+: [Ar]3d^8}

With a weak field ligand like Chloride ion, it shows \mathrm{sp^3} hybridisation 

-

Electronic configuration of \mathrm{Fe^2^+: [Ar]3d^6}

With a weak field ligand like Chloride ion, it shows \mathrm{sp^3} hybridisation and tetrahedral geometry.

-

Electronic configuration of \mathrm{Cu^2^+: [Ar]3d^9}

Hence, it has \mathrm{sp^3} hybridisation and tetrahedral geometry.

-

Therefore, option (1) is correct.

Posted by

Gautam harsolia

View full answer

Similar Questions

Trending Articles/News

anam-khan

TS EAMCET 2025 Cut-off: Top colleges for rank below 10000; TGCHE, JNTUH launch admission drive
anam-khan

JNTU Hyderabad TS EAMCET cut-off trends for BTech; CSE, AI, cybersecurity most sought-after

Latest Question