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Which of the following is  \mathrm{\alpha - D-Glucose}?

Option: 1


Option: 2


Option: 3


Option: 4

None


Answers (1)

best_answer

As we have learnt,

Cyclic structure of glucose -

\mathrm{-CHO} group is absent, the \mathrm{-OH} \mathrm{\left ( at\: C-5 \right )}  group adds to the \mathrm{-CHO} group to form cyclic hemiacetal structure.

In the \alpha form of Glucose, the hydroxyl groups at C-1 and C-2 are aligned parallel while in the \beta form, they are anti parallel. It is to be noted that the Carbonyl carbon is converted into the hemiacetal carbon in the cyclic structure of Glucose.

Thus, the structure of \mathrm{\alpha- D- Glucose} is given as

Hence, the correct answer is Option (3)

Posted by

Ritika Jonwal

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