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  • Which one of the following complexes will most likely absorb visible light? (At no. Sc=21, Ti=22, V=23, Zn=30)Option: 1 <img alt="\mathrm{\

Which one of the following complexes will most likely absorb visible light?

(At no. Sc=21, Ti=22, V=23, Zn=30)

Option: 1

\mathrm{\left[ Sc \left( H _{2} O \right)_{6}\right]^{3+}}


Option: 2

\mathrm{\left[T i\left(NH_{3}\right)_{6}\right]^{4+}}


Option: 3

\mathrm{\left[V\left(N H_{3}\right)_{6}\right]^{3+}}


Option: 4

\mathrm{\left[ Zn \left( NH _{3}\right)_{6}\right]^{2+}}


Answers (1)

best_answer

As we have learnt,

Color due to d-d transition 

When an electron jumps from \mathrm{t_{2g}} to \mathrm{e_g} in octahedral field, it absorbs energy and gets excited.  During de-excitation, it returns back to the initial energy level and releases the energy. This is called d-d transition. Color is often attributed to these d-d transitions.

Out of the given species, only \mathrm{V^{3+}} having \mathrm{3d^{2}} configuration is capable of absorbing light and can show d-d transition.

Other species like \mathrm{Ti^{4+}} and \mathrm{Sc^{3+}} have a \mathrm{d^{0}} configuration while \mathrm{Zn^{2+}} has a \mathrm{d^{10}}  configuration and are not capable of showing d-d transitions.

Therefore, option (3) is correct.

Posted by

Ritika Jonwal

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