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Which one of the following has largest number of isomers?

Option: 1

\mathrm{\left[R u\left( NH _{3}\right)_{4} C l_{2}\right]^{+}}


Option: 2

\mathrm{\left[ Co \left( NH _{3}\right)_{5} Cl \right]^{2+}}


Option: 3

\mathrm{\left[\operatorname{Ir}\left(P R_{3}\right)_{2} H(C O)\right]^{2+}(R=\text { alkyl group })}


Option: 4

\mathrm{\left[ Co (e n){ }_{2} Cl _{2}\right]^{+}}

\mathrm{(e n=\text { ethylene\ diamine) }}


Answers (1)

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The number of isomers of the respective complexes is given below:

(1) \mathrm{\left [ Ru \left ( NH_{3} \right )_{4}Cl_2\right ]^{+}=two \:isomers}

    \mathrm{(Cl,Cl-cis); (Cl-Cl-trans)}

(2) \mathrm{\left [ Co \left ( NH_{3} \right )_{5}Cl\right ]=Zero \:isomers}

(3) \mathrm{\left [ Ir \left ( PR_{3} \right )_{2}H\left ( CO \right )\right ]^{2+}=two \:isomers}

    Square planar complex of type \mathrm{[Ma_2bc]},has two isomers \mathrm{(a,a-cis);(a,a-trans)}

(4) \mathrm{[ Co ( en )_{2}Cl_{2}]^{+}=three \:isomers}

Cis form is optically active and exists in (d+\ell) pair, trans form is optically inactive

Therefore, option (4) is correct.

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