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Two bodies M and N of equal masses are suspended from two different massless springs of spring constant  k_1\:\: and \:\:k_2    respectively.  If the two bodies oscillate vertically such that their maximum velocities are equal , the ratio of amplitude of M  to that of N is  

A. \frac{k_1}{k_2}                      B. \sqrt{\frac{k_1}{k_2}}                C. \frac{k_2}{k_1}                D.  \sqrt{\frac{k_2}{k_1}}

1 an

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@Jeetu

maximum/ velocity\ in\ osccilation =A\omega \\given A_1\omega _1=A_2\omega_2\\omega=\sqrt{\frac{k}{m}}\ given\ mass\ are\ equal\\\therefore \frac{A_1}{A_2}=\sqrt{\frac{k_1}{k_2}}

maxnnum/velocity in osccilation givenAIL'1 = A2W2 om ega k given mass are equal kl k2
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Safeer PP

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