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Engineering
91 Views   |

An ideal gas undergoes a cyclic process as shown in Figure. Heat absorbed by the system during process CA is :

• Option 1)

• Option 2)

• Option 3)

• Option 4)

As we learned   Isochoric Process - Volume is constant during the process - wherein     Isobaric process - Pressure is constant during the process - wherein      Isobaric  Isochoric  Not Defined               2 - 5  =  -3KJ                     -3 - 5 = -3KJ                         Q+w 8 = Q+3 Q= +5KJ     Option 1)       Option 2) Option 3) Option 4)
Engineering
106 Views   |

For which of the following reactions,  is equal to  ?

• Option 1)

• Option 2)

• Option 3)

• Option 4)

As we learned Molar heat capacity for isobaric process C(p) -   - wherein or     Therefore ;  Option 1)       Option 2) Option 3) Option 4)
Engineering
116 Views   |

The combustion of benzene (l) gives CO2(g) and H2O(l). Given that heat of combustion of benzene at constant volume is −3263.9 kJ mol−1 at 258 C; heat of combustion (in kJ mol−1) of benzene at constant pressure will be :

(R=8.314 JK−1 mol−1)

• Option 1)

−3267.6

• Option 2)

4152.6

• Option 3)

−452.46

• Option 4)

3260

As we learned Molar heat capacity for isobaric process C(p) -   - wherein or     For chemical reactions;          Option 1) −3267.6   Option 2) 4152.6   Option 3) −452.46   Option 4) 3260
Engineering
197 Views   |

Which of the following lines correctly show the temperature dependence of equilibrium constant, K, for an exothermic
reaction ? • Option 1)

A and D

• Option 2)

A and B

• Option 3)

B and C

• Option 4)

C and D

As we learned @1380 For exothermic reaction slope will be positive & intercept may be positive or negative for a graph of so correct graph are A & B   Option 1) A and D Option 2) A and B Option 3) B and C Option 4) C and D
Engineering
130 Views   |

Given:

Free energy change,  for the reaction     will be :

• Option 1)

−112.4 kJ mol −1

• Option 2)

−56.2 kJ mol −1

• Option 3)

−168.2 kJ mol −1

• Option 4)

−208.0 kJ mol −1

As we have learnt,

ΔG{reaction} -

- wherein

Sum of   of all product

Sum of   of all reactant

Option 1)

−112.4 kJ mol −1

Option 2)

−56.2 kJ mol −1

Option 3)

−168.2 kJ mol −1

Option 4)

−208.0 kJ mol −1

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Engineering
799 Views   |

fG0 at 500 K for substance ‘S’ in liquid state and gaseous state are +100.7 kcal mol −1 and +103 kcal mol−1 , respectively. Vapour pressure of liquid ‘S’ at 500 K is approximately equal to :
(R=2 cal K−1 mol−1 )

• Option 1)

0.1 atm

• Option 2)

1 atm

• Option 3)

10 atm

• Option 4)

100 atm

As we have learnt,   Δ G of equilibrium -   - wherein At Equilibrum     and     Option 1) 0.1 atm Option 2) 1 atm Option 3) 10 atm Option 4) 100 atm
Engineering
82 Views   |

For which of the following processes, ΔS  is negative ?

• Option 1)

• Option 2)

• Option 3)

• Option 4)

As we have learned Change in entropy for ideal gas in terms of C(p) - - wherein Molar heat capacity at constant pressure       for isothermal process            Option 1) This is incorrect Option 2) This is correct Option 3) This is incorrect Option 4) This is incorrect
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