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Engineering
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Xenon hexafluoride on partial hydrolysis produces compounds ‘X’ and ‘Y’. Compounds ‘X’ and ‘Y’ and the oxidation state of Xe are respectively :

  • Option 1)

    XeO_{2}\left ( +4 \right )\: and\: XeO_{3}\left ( +6 \right )

     

     

     

  • Option 2)

    XeOF_{4}\left ( +6 \right )\: and\: XeO_{3}\left ( +6 \right )

  • Option 3)

    XeO_{2}F_{2}\left ( +6 \right )\: and\: XeO_{2}\left ( +4 \right )

  • Option 4)

    XeOF_{4}\left ( +6 \right )\: and\: XeO_{2}F_{2}\left ( +4 \right )

 
As we learned    Oxy fluoride of Xenon - XeF4+H2O XeF6+H2O XeF6+2H2O - wherein Fluoride of Xe partially hydrolyse by water to give oxy  fluoride of Xe       Option 1)       Option 2) Option 3) Option 4)
Engineering
76 Views   |  

Identify the pair in which the geometry of the species is T-shape and squarepyramidal, respectively :

  • Option 1)

    CIF_{3}\; \; and\; \; \; IO_{4}^{-}

     

     

     

  • Option 2)

    ICl_{2}^{-}\; \; and\; \; \; ICl_{5}^{}

  • Option 3)

    XeOF_{2} \; \; \; and\; \; \; XeOF_{4}

  • Option 4)

    IO_{3}^{-}\; \; \; and\; \; \; IO_{2}F_{2}^{-}

 
As we learned  @4740 @4749   Option 1)       Option 2) Option 3) Option 4)
Engineering
306 Views   |  

In graphite and diamond, the percentage of p-characters of the hybrid orbitals in hybridisation are respectively :

  • Option 1)

    33 and 25

  • Option 2)

    33 and 75

  • Option 3)

    50 and 75

  • Option 4)

    67 and 75

 
 As we learned   Graphite - C atom is sp2 hybridised and thermodynamically more stable than diamond at ordinary temperature  - wherein High electrical conductivity is due to presence of delocalised  electron cloud.     Diamond - C atom is sp3 hybridised and has three dimensional network structure - wherein It is bad conductor due to absence of valence electron     Graphite  hybridization  % = ...
Engineering
97 Views   |  

The compound that does not produce nitrogen gas by the thermal decomposition is :

  • Option 1)

    (NH_{4})_{2}SO_{4}

  • Option 2)

    Ba(N_3)_2

  • Option 3)

    (NH_4)_2Cr_2O_7

  • Option 4)

    NH_4NO_2

 
As we learned Laboratory method of nitrogen preparation - By heating an aqueous solution of NH4Cl and NaNO2 - wherein       Option 1) Option 2) Option 3) Option 4)
Engineering
169 Views   |  

When metal ‘M’ is treated with NaOH, a white gelatinous precipitate ‘X’ is obtained, which is soluble in excess of NaOH.
Compound ’X’ when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ‘M’ is :

  • Option 1)

    Fe
     

  • Option 2)

    Zn
     

  • Option 3)

     Ca
     

  • Option 4)

     Al

 
As we learned Reaction of aluminium with alkalies - Reacts with aqueous alkali and liberates H2 - wherein     (Amphoteric metals are excess so lub le in alkali)            galatinous white                                                                                                     Option 1) Fe   Option 2) Zn   Option 3)  Ca   Option 4)  Al
Engineering
118 Views   |  

Lithium aluminium hydride reacts with
silicon tetrachloride to form :

  • Option 1)

    LiCl, AlH3 and SiH4

  • Option 2)

    LiCl, AlCl3 and SiH4

  • Option 3)

    LiH, AlCl3 and SiCl2

  • Option 4)

    LiH, AlH3 and SiH4

 

As we has learnt,

 

Sheet silicates -

Sharing of three oxygen atoms per tetrahedron resulting in an infintetwo dimensional sheet of primary unit \left ( Si_{2}O_{5} \right )_{n}^{2n-}which are held together by electrostatic force

- wherein

Eg. Talc \left [ Mg_{3}\left ( OH \right )_{2} \left ( SiO_{10} \right ) \right ],Mica, Clay

 

 LiAlH_{4} + SiCl_{4}\rightarrow LiCl + AlCl_{3} + SiH_{4}

 

 


Option 1)

LiCl, AlH3 and SiH4

Option 2)

LiCl, AlCl3 and SiH4

Option 3)

LiH, AlCl3 and SiCl2

Option 4)

LiH, AlH3 and SiH4

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Engineering
236 Views   |  

The number of P−O bonds in P4O6 is :

  • Option 1)

    6

  • Option 2)

    9

  • Option 3)

    12

  • Option 4)

    18

 
As we have learnt,   Phosphorus pentaoxide - P4O10, white solid, formed when P4 is burnt in excess of air - wherein     Phoshorous trioxide - P4O6, dimer, white solid, obtained by burning phosphorus in limited amount of air - wherein    The number of P-O bonds in P4O6 is 12     Option 1) 6 Option 2) 9 Option 3) 12 Option 4) 18
Engineering
80 Views   |  

Among the oxides of nitrogen : N_{2}O_{3},N_{2}O_{4} and N_{2}O_{5} ; the molecule(s)
having nitrogen-nitrogen bond is/are :

  • Option 1)

    only N_{2}O_{5}

  • Option 2)

    N_{2}O_{3} andN_{2}O_{5}

  • Option 3)

    N_{2}O_{4} andN_{2}O_{5}

  • Option 4)

    N_{2}O_{3} andN_{2}O_{4}

 
  As we have learned Dinitrogen trioxide - N2O3(+3), blue liquid - wherein     Dinitrogen tetraoxide - N2O4 (+4), colourless liquid - wherein     N2O3 and N2O4 have nitrogen - nitrogen bond     Option 1) only  This is incorrect Option 2)  and This is incorrect Option 3) This is incorrect Option 4) This is correct
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