# There is a vessel holding 40 litres of milk. 4 litres of milk is initially taken out from the vessel and 5 litres of water is poured in. After this, 5 litres of the mixture from this vessel is replaced with 6 litres of water. And finally 6 litres of mixture from this vessel is replaced with 7 litres of water. How much of the milk (in litres) is there is the vessel now? Option 1) Option 2) Option 3) Option 4) Option 5)

40 L milk from which 4L drawn out

So $40 \times 0.9 = 36 \:L$ milk + 5 liter water

Milk $= 36 \times(1-\frac{5}{41})$

$= 31.6 L + 11L$  water

Now $= 31.6 \times (1- \frac{6}{42.6})$

= 27.09 L milk + (11+7) water

Means = 27.09 L milk + 18 liter water

So final milk $= 27.09\: L$

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