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The\: L.C.M \: of \: 4.5, 0.009,\: and \: 0.18 =?

 

  • Option 1)

     

    4.5

     

  • Option 2)

     

    0.255

     

  • Option 3)

     

    2.25

     

  • Option 4)

     

    45

     

  • Option 5)

     

    None of these

     

The number can be written as, 45/10, 9/1000, 9/50 LCM = LCM of Numerator/HCF of Denominator         = LCM of (45, 9, 9)/ HCF of (10, 1000, 50)         = 45/10 => 4.5 

 

Find the greatest number of four digits which when divided by 10, 11, 15, and 22 leaves 3, 4, 8 and 15 as remainders respectively.

 

  • Option 1)

     

    9907

     

  • Option 2)

     

    9902

     

  • Option 3)

     

    9903

     

  • Option 4)

     

    9100

     

  • Option 5)

     

    None\: of\: these

     

LCM of 10, 11, 15, 22 = 330 largest 4-digit number = 9999 Remainder when 9999/330 = 9900 to make it divisible by 330 9900-7 => 9893

 

Two numbers are in the ratio 17:13. If their HCF is 15, what are the numbers?

 

  • Option 1)

     

    255, 195

     

  • Option 2)

     

    265, 185

     

  • Option 3)

     

    135, 39

     

  • Option 4)

     

    None\: of\: these

     

  • Option 5)

     

    -

     

Numbers (17 x 15 & 13 x 15) = 255 & 195  

 

   On Ashok Marg three consecutive traffic lights change after 36, 42 and 72 seconds respectively. If the lights are first switched on at 9:00 A.M. sharp, at what time will they change simultaneously?

 

  • Option 1)

     

    9 : 08 : 04

     

  • Option 2)

     

    9 : 08 : 24

     

  • Option 3)

     

    9 : 08 : 44

     

  • Option 4)

     

    None\: of\: these

     

  • Option 5)

     

    -

     

LCM of 36, 42, 72 = 504 seconds or 8 min 24 seconds Required Time = 9:00 + 8 min 24 seconds                            = 9: 08: 24

 

X, Y, Z start at the same time in the same direction to run around a circular stadium. X completes a round in 63 seconds, Y in 105 seconds and Z in 210 seconds. If they start at the same time, then at what time will they meet again at the starting point?

 

  • Option 1)

     

    9 \: min \: 9 \: seconds

     

  • Option 2)

     

    10 \: min\: 30\: seconds

     

  • Option 3)

     

    10\: min \: 6 \: seconds

     

  • Option 4)

     

    8 \: min \: 4 \: seconds

     

  • Option 5)

     

    -

     

X = 63 Y = 105 Z = 210 LCM of X,Y & Z = 630 Seconds or 10 min & 30 seconds

 

 Four different devices beep after every half hour, 60 min, 1 and half hours, and 135 min respectively. All the devices beeped together at 12 noon. They will beep together again at:

 

  • Option 1)

     

    12 Midnight

     

  • Option 2)

     

    6 AM

     

  • Option 3)

     

    9 PM

     

  • Option 4)

     

    7: 30 AM

     

  • Option 5)

     

    9 AM

     

A = 30 min B = 60 min C = 90 min D = 105 min LCM of ABCD = 1260 min or 21 hours Required Time = 12 Noon + 21 => 9AM

The least number which when divided by 5, 6, 7, and 8 leaves the remainder 3. But when divided by 9 leaves no remainder, is:

  • Option 1)

    1766

  • Option 2)

    1683

  • Option 3)

    2327

  • Option 4)

    1895

  • Option 5)

    -

 

Find the least multiple of 23 which when divided by 24, 21, and 18 leaves the remainders 13, 10, and 7 respectively

  • Option 1)

    3004

  • Option 2)

    3024

  • Option 3)

    3013

  • Option 4)

    3026

  • Option 5)

    -

 

 The smallest number which when diminished by 5 becomes divisible by 12, 16, 18, 21, and 28

  • Option 1)

    1015

  • Option 2)

    1013

  • Option 3)

    1022

  • Option 4)

    1017

  • Option 5)

    -

 

What will be the least number which when doubled becomes exactly divisible by 9, 15, 21, and 30?

  • Option 1)

    196

  • Option 2)

    189

  • Option 3)

    630

  • Option 4)

    315

  • Option 5)

    -

 

 

The greatest number, which when divides 1358, 1870, and 2766 leaves the same remainder 14 in each case, is:

 

  • Option 1)

     

    124

     

  • Option 2)

     

    64

     

  • Option 3)

     

    156

     

  • Option 4)

     

    260

     

  • Option 5)

     

    -

     

The greatest number, which when divides 1358, 1870, and 2766 leaves the same remainder 14 in each case, is:  

 

 Find the greatest number that will divide 48, 97 and 188 and leaves the reminder 6 in each case.

 

  • Option 1)

     

    4

     

  • Option 2)

     

    7

     

  • Option 3)

     

    2

     

  • Option 4)

     

    6

     

  • Option 5)

     

    -

     

The greatest number that will divide 48, 97 and 188 and leaves the remainder 6 in each case is:  

What is the maximum number of students among whom 1095 pens and 1168 pencils can be distributed in such a way that each student gets equal number of pens and equal number of pencils.

  • Option 1)

    71

  • Option 2)

    73

  • Option 3)

    63

  • Option 4)

    65

  • Option 5)

    -

 

The greatest possible length which can be used to measure exactly the lengths: 20 m 6 cm, 11m 90 cm and 14 m 45 cm is:

 

 

 

  • Option 1)

    17

  • Option 2)

    18

  • Option 3)

    19

  • Option 4)

    121

  • Option 5)

    -

 
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