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There are two containers: the first contains 500ml of alcohol, while the second contains 500 ml of water. Three cups of alcohol from the first container is removed and is mixed well in the second container. Then three cups of this mixture is removed and is mixed in the first container. Let ‘A’ denote the proportion of water in the first container and ‘B’ denote the proportion of alcohol in the second container. Then A,

• Option 1)

• Option 2)

• Option 3)

• Option 4)

Cannot be determined

• Option 5)

Let the capacity of each = 100 ml So 300 ml removed and poured into second First vessel = 200 ml alcohol Second = 500 ml water+ 300 ml A Ratio = 5:3 Proportion of alcohol = 3/8 If 300 ml removed from second  = 300 x 5/8 = 187.5 ml water = 112.5 ml alcohol Now poured so vessel = 200 + 112.5 = 312.5 A = 187.5 ml Hence ratio = 5:3 proportion of water = 3/8 So A= B

Ram prepares solutions of alcohol in water according to customer’s needs. This morning Ram has prepared 27 litres of a 12% alcohol solution and kept it ready in a 27 litre delivery container to be shipped to the customer. Just before delivery, he finds out that the customer had asked for 27 litres of 21% alcohol solution. To prepare what the customer wants, Ram replaces a portion of 12% solution by 39%  solution. How many litres of 12% solution are replaced?

• Option 1)

• Option 2)

• Option 3)

• Option 4)

• Option 5)

Direct solution
Spirit in first = 8/8+3 = 8/11 Spirit in second = 5/6 Spirit in mixture = 4/5  Ratio    From first vessel taken
40 L milk from which 4L drawn out So milk + 5 liter water  Milk   water Now = 27.09 L milk + (11+7) water Means = 27.09 L milk + 18 liter water So final milk
Here y = 4 and n = 2 By solving above equation we get X = 28

How many litres of water should be added to 25 litres of milk costing Rs. 12 per litre, so that by selling the mixture at the cost price, profit of 20% is made ?

• Option 1)

3 litres

• Option 2)

5 litres

• Option 3)

8 litres

• Option 4)

10 litres

• Option 5)

2 litres

CP of milk = 12 CP of mixture = Water                Milk X                      25L             10 2          :           10

The cost price of a table is Rs 330. It is sold for a profit of Rs 30 after giving 10% discount.find its marked price

• Option 1)

Rs 400

• Option 2)

Rs 380

• Option 3)

Rs 420

• Option 4)

340

• Option 5)

none

CP = 330             SP = 360 MP = ? MP = 400

If after giving a discount of 12%, a profit of 10% was made on an article, then by what % was the price marked up ?

• Option 1)

18%

• Option 2)

25%

• Option 3)

32.5%

• Option 4)

35%

• Option 5)

20%

Let CP = 100            MP = ? SP = 110 .88 MP = 110 MP =

An item was sold at a price after giving two successive discount  of 30% and 50 %. If the selling price of the item was Rs 448, then what was the marked price of the item ?

• Option 1)

840

• Option 2)

1280

• Option 3)

1140

• Option 4)

1521

• Option 5)

1640

MP = ?

A dealer sold two of his cattle for Rs. 500 each. On one of them he lost 10% on the other, he gained 10%. His gain or loss percent in the entire transaction was :

• Option 1)

10% loss

• Option 2)

1% loss

• Option 3)

1% gain

• Option 4)

11% loss

• Option 5)

10% gain

SP of two cattles = Rs 500 each One lost= 10% One gain =10% Loss %  =

Ajay bought 15 kg of dal at the rate of Rs 14.50 per kg and 10 kg at the rate of Rs 13 per kg. He mixed the two and sold the mixture at the rate of Rs 15 per kg. What was his total gain in this transaction ?

• Option 1)

Rs 9.5

• Option 2)

Rs 11

• Option 3)

Rs 16.5

• Option 4)

Rs 27.5

• Option 5)

Rs 1.1

1st dal cost = 2nd dal cost = Total cost =  347.5 SP = Profit =

If books bought at prices ranging from Rs. 200 to Rs. 350 are sold at prices ranging from Rs.300 to Rs. 425, what is the greatest possible profit that might be made in selling eight books ?

• Option 1)

600

• Option 2)

1400

• Option 3)

1800

• Option 4)

none

• Option 5)

1200

if CP is least and SP is max only then gratest profit will occur let CP = 200     SP = 425 P = 225 per book Then profit of 8 books =

A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is :

• Option 1)

9%

• Option 2)

5%

• Option 3)

8%

• Option 4)

10%

• Option 5)

no profit no loss

1st type rice =  1st type rice =  Total cost = 1600 S.P = Profit % =

A dozen pairs of gloves quoted at Rs. 80 are available at a discount of 10%. Find how many pairs of gloves can be bought for Rs. 24.

• Option 1)

4

• Option 2)

3

• Option 3)

6

• Option 4)

8

• Option 5)

5

Dozen pairs of gloves quoted at = Rs 80 1 pair gloves quoted at = After discount = In Rs 24 = = 4 pairs

125 toffees cost Rs. 75, Find the cost of one million toffees if there is a discount of 40% on the selling price for this quantity.

• Option 1)

Rs. 3,00,000

• Option 2)

Rs. 3,20,000

• Option 3)

Rs 3,60,000

• Option 4)

Rs. 3,80,000

• Option 5)

Rs. 4,00,000

125 toffees cost = 75 1 toffees = 1 million toffees =  After discount =

By selling bouquets for Rs. 63, florist gains 5%. At what price should he sell the bouquets to gain 10% on the cost price?

• Option 1)

Rs.66

• Option 2)

Rs. 69

• Option 3)

Rs.80

• Option 4)

Rs. 72.50

• Option 5)

Rs. 72

A shopkeeper sold goods for Rs. 2400 and made a profit of 25% in the process. Find his profit percent if he had sold his goods for Rs. 2040.

• Option 1)

6.25%

• Option 2)

8%

• Option 3)

6.20%

• Option 4)

6.5%

• Option 5)

7%

CP = ? SP = 2400 1.25 CP = 2400 By solving this CP = 1920

There are two alloys made up of copper and aluminium. In the first alloy copper is half as much as aluminium and in the second alloy copper is thrice as much as aluminium. How many times the second alloy must be mixed with first alloy to get the new alloy in which copper is twice as much as aluminium?

• Option 1)

• Option 2)

1

• Option 3)

• Option 4)

• Option 5)

C   :     A                  first            1    :      2                second        3    :      1                   third          2   :       1   Ratio = 1:4 So 4 times second alloy should be mixed with first to get desired ratio
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