25ml of solution containing HCl and H2SO4 require 25ml of 0.5M caustic soda for complete neutralization. 50ml of the same solution on precipitation with excess BaCl2 gave 2.33g of precipitate BaSO4. What is the strength of HCl in the solution(in g/L)?
36.5
3.65
7.3
73
Let molarity of HCl and H2SO4 be x and y respectively.
Now, upon neutrlization, we have:
25(x+2y) = 25 x 0.5
x + 2y = 0.5
Next, upon precipitation, we have:
50 x y = (2.33/233) x 1000 = 10
y = 0.2 and x = 0.1
Thus, molarity of HCl = 0.1
It means 3.65 g/L of HCl is present in the stock solution.