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  • A bulb is rated at 100 V,100 W , it can be treated as a resistor. Find out the inductance of an inductor (called choke coil) that should be connected in series with the bulb to operate the bulb at

A bulb is rated at 100 V,100 W , it can be treated as a resistor. Find out the inductance of an inductor (called choke coil) that should be connected in series with the bulb to operate the bulb at its rated power with the help of an ac source of 200 V and 50 Hz.

Option: 1

\frac{\pi }{\sqrt{3}}H

 

 

 


Option: 2

100\, H


Option: 3

\frac{\sqrt{2}}{\pi }H


Option: 4

\frac{\sqrt{3}}{\pi }H


Answers (1)

best_answer

From the rating of the bulb, the resistance of the bulb can be calculated.

R=\frac{V_{rms}^{2}}{P}=100\: \Omega

For the bulb to be operated at its value the rms current through it should be 1A

Also, I_{rns}= \frac{V_{rms}}{Z}\Rightarrow 1=\frac{200}{\sqrt{100^{2}+\left ( 2\pi 50L \right )^{2}}} 

So  L=\frac{\sqrt{3}}{\pi }H

Posted by

manish painkra

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