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  • A clock with a metal pendulum beating seconds keep correct time at . If it loses 12.5 s a da

A clock with a metal pendulum beating seconds keep correct time at 0^{0}\textrm{C}. If it loses 12.5 s a day at 25^{0}\textrm{C}, the coefficient of linear expansion of metal pendulum is 

Option: 1

\frac{1}{86400}/^{0}\textrm{C}

 

 

 


Option: 2

\frac{1}{43200}/^{0}\textrm{C}


Option: 3

\frac{1}{14400}/^{0}\textrm{C}


Option: 4

\frac{1}{28800}/^{0}\textrm{C}


Answers (1)

best_answer

As we learned

Effect of temperature on Simple Pendulum -

\frac{\Delta T}{T}=\frac{1}{2}\;\alpha\; \Delta \theta

- wherein

\Delta \theta=\theta-\theta_{0}

\Delta \theta= Change in temperature

 

\frac{\Delta T}{T}=\frac{1}{2}\alpha \Delta \theta  or \Delta T = \frac{1}{2}\alpha \Delta \theta \cdot T

\Rightarrow 12.5=\frac{1}{2}\times 2\times 25\times 86400

or  \alpha =\frac{1}{86400}/^{0}\textrm{C}

Posted by

himanshu.meshram

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