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  • A current of 5 amp is passed for one hour through an aqueous solution of copper sulphate using copper electrodes. What is the change in the mass of the cathode?O

A current of 5 amp is passed for one hour through an aqueous solution of copper sulphate using copper electrodes. What is the change in the mass of the cathode?

Option: 1

3.17


Option: 2

5.92


Option: 3

4.92


Option: 4

5.72


Answers (1)

best_answer

The reaction occuring at the given cathode is 

 \mathrm{Cu^{2+} + 2e^-\rightarrow Cu (Cathode )}

Thus, 1 mole of \text{Cu} is deposited by the passage of 2 moles of electrons.

So, charge required to deposit 1 mole of \text{Cu}= 2 \times 96500=193000 \text{~C}

Now,

Actual charge passed through the electrode \mathrm{= 5 \times 60 \times 60 = 18000 ~C}

So, moles of \mathrm{Cu} deposited = \frac{18000}{193000}

Thus, mass of copper deposited \mathrm{= \frac{18000}{193000} \times 63.5 = 5.92 ~g}

Posted by

sudhir.kumar

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