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A force of F = 70 N is applied on a block of mass M = 10 Kg placed on a horizonatl surface as shown in the figure . What will be the work (Joule) done by frictional force in t = 2 sec if block was initially at rest 

Option: 1 0

Option: 2 10

Option: 3 50

Option: 4 40

Answers (1)

best_answer

As we have learned

Limiting friction 

F_L = \mu N \\ \mu mg = 0.8 \times 10 \times 10 = 80N

Applied force F = 70 N 

F_L > F 

So body will not move displacement s = 0 

W = 0 

 

 

 

 

Posted by

Riya

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