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A particle of mass M moves along x-axis with speed v_0 and collides and stick to mass 'm' moving with speed v_0 along y- axis . The velocity of the combined particle after the collision 

Option: 1

\frac{M\hat i + m \hat j}{(M+m)} v_0


Option: 2

\frac{m \hat i + M \hat j }{M+ m } v_0


Option: 3

( m \hat i + M \hat j ) v_0


Option: 4

\frac{M \hat i + m \hat j }{M } v_0


Answers (1)

best_answer

As we have learned

Perfectly Inelastic Collision -

e=0

- wherein

\! e\: :\: coeffecient\: of \: restitution

Two bodies stick together after the collision in case of inelastic collision ,so there will be a final common velocity and \small v_{2}=v_{1} 

So, e=0

 

 By momentum conservation 

Mv_0 \hat i + m v_0 \hat j = (m + M ) \vec v

\vec v = 

\frac{M\hat i + m \hat j}{(M+m)} v_0

 

Posted by

jitender.kumar

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