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1547444587624-1279057330.jpg A pulley is atttached to the ceiling of a lift moving upward. Two particles are attached to the two ends of a string passing over the pulley. The masses of the particles are in the ratio 2:1. If the acceleration of the particles is g/2 then acc of lift?

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@Gourav

Given  acceleration of the particles is g/2=a'

now let acceleration of the lift=a upwards

assume lift at rest and apply psudo force=mass* a to both masses

Let masses as 2m and m

2m>m so 2m will move downward with a'

So 2mg+2ma-T=2ma'=2m(g/2)=mg .....(1)

and similarly for m mass

T-mg-ma=ma'=m(g/2) .....(2)

Solving both we get 

a=(g/2)

 

 

 

Posted by

avinash.dongre

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