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  • A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. The power of the pulse is 36 mW and the speed of light is 3 * 108 m/s. The final mome

A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. The power of the pulse is 36 mW and the speed of light is 3 * 108 m/s. The final momentum of the object is:

Option: 1

0.3 * 10-17 kg m/s


Option: 2

1.0 * 10-17 kg m/s


Option: 3

3 * 10-17 kg m/s


Option: 4

9.0 * 10-17 kg m/s


Answers (1)

best_answer

E = mc2

Also, E = p * t = 30 * 10-13 * 100 * 10-9 J = mc2

\implies 3 * 10-9 = m * (3 * 108)2 = m * 9 * 30 * 1016

\implies m = \frac{1}{3} * 10^{-25}

Since p = mv:

p = \frac{1}{3} * 10^{-25} * 3 * 10^{8}

    = 10-17 kg m/s

Posted by

Rishabh

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