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A reaction at 1 bar is non-spontaneous at low temperature but becomes spontaneous at high temperature.  Identify the correct statement about the reaction among the following :

Option: 1

Both ∆H and ∆S are negative.


Option: 2

Both ∆H and ∆S are positive.


Option: 3

H is positive while ∆S is negative.


Option: 4

H is negative while ∆S is positive.


Answers (1)

best_answer

ΔG=ΔH−TΔS

At low temperature,
TΔS < ΔH
ΔG > 0 and the reaction is non-spontaneous.

At high temperature,
TΔS > ΔH
ΔG < 0 and the reaction is spontaneous.

Posted by

manish painkra

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