A reaction at 1 bar is non-spontaneous at low temperature but becomes spontaneous at high temperature. Identify the correct statement about the reaction among the following :
Both ∆H and ∆S are negative.
Both ∆H and ∆S are positive.
∆H is positive while ∆S is negative.
∆H is negative while ∆S is positive.
ΔG=ΔH−TΔS
At low temperature,
TΔS < ΔH
ΔG > 0 and the reaction is non-spontaneous.
At high temperature,
TΔS > ΔH
ΔG < 0 and the reaction is spontaneous.