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A simple pendulum is released from A as shown in the figure. If m and l represent the mass of the bob and the length of the pendulum respectively, the gain in kinetic energy at B is then

Option: 1

\frac{mgl}{\sqrt 2 }


Option: 2

\frac{mgl }{2}


Option: 3

\frac{\sqrt 3}{2}mgl


Option: 4

\frac{2 }{\sqrt 3} mgl


Answers (1)

Initial energy = mgl

But, as per the given in question, PE=0

gain in \mathrm{KE}=\mathrm{mg}l \cos 30

\mathrm{KE}=\mathrm{mg} \frac{\sqrt{3}}{2}

\therefore option C is the correct solution

Posted by

Kshitij

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