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  • A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work re

A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on to the table is  

Option: 1

MgL


Option: 2

\frac{MgL}{3}


Option: 3

\frac{MgL}{9}


Option: 4

\frac{MgL}{18}


Answers (1)

best_answer

 

 

So,

As 1/3 part of the chain is hanging from the edge of the table. So by substituting n = 3 in standard expression 

We get : W = \frac{MgL}{2n^{2}}= \frac{MgL}{2(3)^{2}}= \frac{MgL}{18}

Posted by

Gunjita

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