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  • Acceleration of the particle is given by the relation , where <img

Acceleration of the particle is given by the relation a=\alpha t+\beta t^2, where \alpha and \beta are positive constant, displacement of the particle is proportional to

Option: 1

t^4


Option: 2

t^{\circ}


Option: 3

t^2


Option: 4

None of these.


Answers (1)

best_answer

Acceleration (a) =\alpha t +\beta t^2
v=\int a d t =\frac{\alpha t^2}{2}+\frac{\beta t^3}{3}
position (displacement) =\int v d t
=\frac{\alpha t^3}{6}+\frac{\beta t^4}{12}

Posted by

Ritika Jonwal

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