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# An ammeter reads upto 1amp. Internal resistance of Â ammeter is 0.81. To increase the range to 10A, the value of required shunt i

An ammeter reads up to 1A. Internal resistance of Â ammeter is 0.81 ohm. To increase the range to 10 A, the value of required shunt is
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I is the required current=10A. Ig =1 A , G=0.81 ohm, find S (shunt required)

$\frac{S}{S+G}=\frac{I_{g}}{I}\Rightarrow S=\frac{I_{g}G}{I-I_{g}}$

$\therefore \; \; \; S=\frac{1\times 0.81}{10-1}=\frac{0.81}{9}=0.09\, \Omega \; in\; parallel.$

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