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  • Arrange in increasing order of oxidation number of N. <img alt="\mathrm{NH_3,N_3H,NH_2OH,N_2O}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BNH_3%2CN_3H%2CNH_2OH%2CN_2

Arrange in increasing order of oxidation number of N.

\mathrm{NH_3,N_3H,NH_2OH,N_2O}

Option: 1

\mathrm{NH _{3}, N _{3} H, NH _{2} OH , N _{2} O}


Option: 2

\mathrm{N _{2} O , N _{3} H , NH _{2} OH , NH _{3}}


Option: 3

\mathrm{N _{2} O , NH _{2} OH , N _{3} H , NH _{3}}


Option: 4

\mathrm{NH _{3}, NH _{2} OH , N _{3} H , N _{2} O}


Answers (1)

best_answer

Oxidation Number -

Oxidation number denotes the oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belongs entirely to more electronegative elements.

 

 In \mathrm{NH_3,O.N.(N)+3O.N.(H)=0}

\mathrm{O.N.(N)=-3}

In \mathrm{N_3H,\: 3O.N.(N)+O.N.(H)=0}

\mathrm{O.N.(N)=\frac{-1}{3}}

In \mathrm{NH_2OH,\: O.N.(N)+2O.N.(H)+O.N.(OH)=0}

\mathrm{O.N.(N)+2-1=0}

\mathrm{O.N.(N)=-1}

In \mathrm{N_2O,\: 2O.N.(N)+O.N.(O)=0}

\mathrm{O.N.(N)=+1}

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Ritika Harsh

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