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  • Arrange the following in increasing order of oxidation number of Fe: <img alt="\mathrm{Fe_2O_3,Fe,Fe_3O_4}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BFe_2O_3%2CFe%2CFe_3O_4%7

Arrange the following in increasing order of oxidation number of Fe: \mathrm{Fe_2O_3,Fe,Fe_3O_4}

Option: 1

\mathrm{F e, Fe _{3} O _{4}, Fe _{2} O _{3}}


Option: 2

\mathrm{Fe _{3} O _{4}, F e, Fe _{2} O _{3}}


Option: 3

\mathrm{Fe _{2} O _{3}, Fe _{3} O _{4}, Fe}


Option: 4

\mathrm{Fe , Fe _{2} O _{3}, Fe _{3} O _{4}}


Answers (1)

best_answer

 for  \mathrm{Fe_2O_3}

2(Fe)+3(O)=0

2(Fe)=+3x2

(Fe)=+3

 

for \mathrm{Fe_3O_4}

3(Fe)+4(O)=0

3(Fe)=8

(Fe)=+8/3

 

for  Fe

(Fe)=0  as in the free state, each atom has an O.N. of 0

 

Order will be 0 < +8/3 < +3

So, the increasing order of oxidation state is 

\mathrm{Fe,Fe_3O_4,Fe_2O_3}

Hence, the correct answer is Option (1)

Posted by

shivangi.bhatnagar

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