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At \small 27^{\circ} \mathrm{C} initial gauge pressure of a cylinder having 20 litre oxygen is \small 15 \mathrm{~atm}. After taking some out the pressure drops to \small 20 \mathrm{~atm} temperature remains same. What is the mass of gas taken out.

Option: 1

130 gm


Option: 2

120 gm


Option: 3

128 gm


Option: 4

129 gm


Answers (1)

best_answer

\begin{aligned} & V_1=20 \times 10^{-3} \mathrm{~m}^3=v_2 \\ & T=300 \mathrm{~K}, P_1=1.5 \times 1.01 \times 10^5 \mathrm{Nm}^{-2} \\ & P_2=10 \times 1.01 \times 10^5 \mathrm{Nm}^{-2} \end{aligned}

\begin{aligned} P_1 V_1 & =n_1 R T_1 \\ n_1 & =\frac{13 \times 1.01 \times 10^5 \times 20 \times 10^{-3}}{8.3 \times 300} \end{aligned}

\begin{aligned} n_1 & =12.1 \\ n_2 & =\frac{10 \times 1.01 \times 10^5 \times 20 \times 10^{-3}}{8.3 \times 300} \end{aligned}

\begin{aligned} &n_2=0.1\\ &\begin{aligned} \text { No. of moles taken out } & =12.1-0.1 \\ & =4 \end{aligned} \end{aligned}

\text { Mass of } 4 \text { moles }=4 \times 32=128 \mathrm{gm}

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