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At resonance the impedance of given circuit

Option: 1

\sqrt{R^{2}+(X_{L}-X_{C})^{2}}

 

 


Option: 2

\sqrt{R^{2}+X_{L}^{2}}


Option: 3

\sqrt{R^{2}+X_{C}^{2}}


Option: 4

R


Answers (1)

best_answer

As we learned

 

At resonance (series resonant and circuit) If X_{L}=X_{c} -

Z_{min}= R

- wherein

Circuit behaves as resistive circuit.

 

 

At resonance, X_{L}=X_{C}

\Rightarrow Z=\sqrt{R^{2}+(X_{L}-X_{C})^{2}}

\Rightarrow Z=\sqrt{R^{2}}

Z = R

Posted by

mansi

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