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  • At resonance , the phase difference of LCR circuit isOption: 1 0Option: 2 <img alt="\frac{\

At resonance , the phase difference of LCR circuit is

Option: 1

0


Option: 2

\frac{\pi}{2}


Option: 3

\pi


Option: 4

2\pi


Answers (1)

best_answer

Phase difference of LCR circuit

\phi = tan^{-1}\left ( \frac{X_{L} - X_{C}}{R} \right )

At resonance , XL = XC

\phi = tan^{-1}\left ( \frac{0}{R} \right )

\phi = 0

Posted by

Divya Prakash Singh

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