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  • Balance the following reaction using oxidation number method <img alt="xCr_2O_7^{2-}+ySO_2+zH^+\rightarrow aCr^{3+}+bHSO_4^{-}+cH_2O" src="https://learn.careers360.com/latex-image/?xCr_2O

Balance the following reaction using oxidation number method

xCr_2O_7^{2-}+ySO_2+zH^+\rightarrow aCr^{3+}+bHSO_4^{-}+cH_2O

and find the values of a,b,c,x,y,z.

Option: 1

x=2,y=3,z=5,a=4,b=3,c=1


Option: 2

x=1,y=4,z=5,a=2,b=4,c=1


Option: 3

x=1,y=3,z=5,a=2,b=3,c=1


Option: 4

x=1,y=3,z=10,a=2,b=3,c=3


Answers (1)

best_answer

 We have,

Cr_2O_7^{2-}+SO_2+H^+\rightarrow Cr^{3+}+HSO_4^{-}+H_2O

Step1. Write the correct formula for each reactant and product.

Step2. Identify atom whose oxidation number is changed.

\overset{+6}Cr_2O_7^{2-}+\overset{+4}SO_2+H^+\rightarrow Cr^{3+}+H\overset{+6}SO_4^{-}+H_2O

Step3.Multiply by coeff. so that change in oxidation state becomes equal.

Cr_2O_7^{2-}+3SO_2+H^+\rightarrow 2Cr^{3+}+3HSO_4^{-}+H_2O

Step4-5:

Add H^{+}/OH^{-} on the appropriate side so that the total ionic charges of reactants and products are equal.

Make numbers of hydrogen atoms in the expression on the two sides equal by adding H_{2}O to reactant or product

Cr_2O_7^{2-}+3SO_2+5H^+\rightarrow 2Cr^{3+}+3HSO_4^{-}+H_2O
Therefore,option(3) is correct

Posted by

Rakesh

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