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  • Calculate the root mean square speed of molecules of Helium gas at 600 k temperature Respectively. (Given -mass of Hellium molecules =<img alt="=4.6\times 10^{-26}kg, K_{B}=1.4\times 10^{

Calculate the root mean square speed of molecules of Helium gas at 600 k temperature Respectively.

(Given -mass of Hellium molecules ==4.6\times 10^{-26}kg, K_{B}=1.4\times 10^{-23}J/k)

Option: 1

740.15 m/sec


Option: 2

733.3 m/sec


Option: 3

744 m/sec


Option: 4

zero


Answers (1)

best_answer

Given , mass of Helium

\mathrm{\begin{aligned} T & =600 \mathrm{~K} \\ V_{\text {rmas }} & =\sqrt{\frac{3 R T}{m}}=\sqrt{\frac{3 K_B T}{m}} \\ & =\sqrt{\frac{3 \times 1.4 \times 10^{-23} \times 600}{4.6 \times 10^{-26}}} \\ & =740.15 \mathrm{~m} / \mathrm{sec} \end{aligned}}

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jitender.kumar

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